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Old April 20th, 2008, 01:04 PM
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Default How to detect the level of an element

HI

I would like to detect the level of an element in according to his root.
Quote:
quote:
  <Issue issueID="" composer="" date="">
    <Proposition composer="" date="" level="1" actname="proposition">
      <Agreement composer="" date="" level="2"></Agreement>
    </Proposition>
  </Issue>
Suppose that I want to output all elements nested just in the "Issue" element and not in it's sub element and I also don't know their name(Proposition is an example and I have to be able to output even if it changes).

How can I output an element considering the only information I have that element is it's level(from the root), by the way of an attribute("level").

Thanks in advance

Ali

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Old April 20th, 2008, 04:43 PM
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If Issue is the current element then you can process all its children, regardless of their name, using <xsl:apply-templates select="child::node()"/>. In fact child::node() abbreviates to node(), and this is the default for apply-templates anyway.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Old April 20th, 2008, 04:47 PM
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I fear my response probably wasn't very helpful, but it's hard to know where you are having problems. I think it would help if you showed us the output you want to generate, and the code you have written so far.

Michael Kay
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Old April 21st, 2008, 01:11 AM
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Using XPath you can locate an element according to its level attribute with an expression such as this :
Code:
descendant::*[@level=$mylevel]
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