Hi, iam very new to xslt. I need to transform a xml file into another format of xml file, and i only want to display certain contents from the 1st xml file. However, i keep having all the inputs from the 1st xml file. Can anyone help me identify my mistake?

[u]The first xml file</u>
<?xml version="1.0" encoding="UTF-8"?>
<labb xmlns="http://www.*************">
    <header>
        <version>1.2</version>
        <lab>
            <appointed>2</appointed>
            <id>QUEEE</id>
            <name>LL</name>
            <addr>
                <BlkNo>88</BlkNo>
                <StreetName>c</StreetName>
                <FloorNo>00</FloorNo>
                <UnitNo>77</UnitNo>
                <BuildingName>Wonderful land</BuildingName>
                <PostalCode>888888</PostalCode>
            </addr>
            <CMSCode>TTT</CMSCode>
        </lab>
        <clinic>
            <id>cln007</id>
            <name>test clinic</name>
        </clinic>
        <clinic_lab>
            <id>DS011</id>
            <name>test clinic</name>
        </clinic_lab>
        <order_submit_dt>20070908</order_submit_dt>
        <order_status_code>CM</order_status_code>
        <order_control_code>NW</order_control_code>
        <orderby>
            <id>NC</id>
            <name>TEST</name>
        </orderby>
        <priority/>
        <result_dt>20070908163003</result_dt>
        <result_msg_control>ooo</result_msg_control>
        <profile_code_list>X105482</profile_code_list>
        <profile_desc_list>BASIC(GLL)</profile_desc_list>
    </header>
    <patient>
        <name>SAMPLE TESTINg</name>
        <identity>XXX2494221</identity>

        <race>cc</race>
        <dob>19710101</dob>
        <birthYear>
            <YearOfBirth>1988</YearOfBirth>
        </birthYear>

    </patient>
</labb>


[u]
The output xml file is something like the following:</u>
<?xml version="1.0" encoding="utf-8"?>
<Request>
<Client>
        <ClientName>Client Name 01</ClientName>
        <ClientRace>C</ClientRace>
        <ClientGender>F</ClientGender>
        <ClientNRIC>S1234567D</ClientNRIC>
</Client>
<Clinic>
        <Appointed>2</Appointed>
        <ClinicName>Clinic Name 01</ClinicName>
</Clinic>


[u]And I have written a xslt file</u>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" omit-xml-declaration="no" standalone="no" indent="yes" />

    <xsl:template match="/">
        <Request>
            <xsl:apply-templates ></xsl:apply-templates>
        </Request>
    </xsl:template>

    <xsl:template match="/patient">
        <ClientData>
            <ClientName>

              <xsl:value-of select="name"/>

            </ClientName>
            <ClientRace>
                <xsl:value-of select="race" />
            </ClientRace>
            <ClientGender>
                <xsl:value-of select="****" />
            </ClientGender>
</ClientData>
</xsl:template>

</xsl:stylesheet>

 Thanks.

Change match="/patient" to match="patient". The "/patient" form would only match if the patient is the outermost element of the document, which in your case it isn't.

Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer's Reference

Thanks for the reply but I have tried that, and still having the same problem.

Well, I usually only spot one bug at a time when inspecting source code. The next bug (I don't guarantee it is is the last) is that your source document contains elements that are in a namespace, but you are trying to match elements in no namespace. Your stylesheet needs to declare the namespace

xmlns:p="http://www.*************"

and then use this prefix when referring to elements in the source documetn, for example match="p:patient"

Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer's Reference

Thanks..ya, i know it has many bugs. Been struggling to do this. Anyway, i used to delcare the namespace in the sylesheet, but i used "p/patient" instead of p:patient.