tables

rizp · August 17th, 2004, 04:42 PM

Hi -

Does anyone know how to create dynamic tables??? For example, if I enter (into a textbox) the number 3, then a table with three rows should be generated (the columns are preset). So basically, I should be able to input any number X (max 8), then a table with X number of rows should be generated.

Can anyone help please????

rizp

happygv · August 17th, 2004, 05:43 PM

Hi there,

On submit request that number entered and store into a variable.

Start <table> tag before loop.
Then run a loop from 1 till that number and write

Code:

<tr><td>&nbsp;</td></tr>

that many times. Use as many "<td> </td>"s as needed for those number of preset columns.
End the </Table> tag after loop.

Hope that helps.
Cheers!

_________________________
- Vijay G
Strive for Perfection

rizp · August 26th, 2004, 04:40 PM

Hi -

Thanks - that did help, although ive changed my mind as to how i want the tables generated - now I have a drop down list - where the user can select the number of rows they would like - (in total there are 14 different combinations). How can the table be generated on selecting the choice from the list?? So if i select the number 4 - a table with 4 rows should be generated instantly (with or without having a submit button). I also want that table to contain text boxes where the user can enter information - possibly even have drop down lists. This information is then going to be held in a SQL database.

Can you be more specific as to how this table can be generated please??

Many thanks - rizp

mehdi62b · August 27th, 2004, 01:42 AM

if I were you I'd use Table objec(ASP.NET objects),dont work with <td> & <tr>
Have a look at this example

Code:

        void Page_Load(Object sender, EventArgs e) {
            // Generate rows and cells           
            int numrows = 3;
            int numcells = 2;
            for (int j=0; j<numrows; j++) {          
                TableRow r = new TableRow();
                for (int i=0; i<numcells; i++) {
                    TableCell c = new TableCell();
                    c.Controls.Add(new LiteralControl("row " + j.ToString() + ", cell " + i.ToString()));
                    r.Cells.Add(c);
                }
                Table1.Rows.Add(r);
            }
        }

--------------------------------------------
Mehdi.:)