Copying all the nodes except the specific node

Martin Honnen · July 22nd, 2009, 06:49 AM

I am afraid I don't understand what exactly you want to achieve. If you pass in a node and what to check if it is the context node then in XSLT 2.0 you can use 'is' operator, with XSLT 1.0 you can use generate-id on each node and compare the result.

Some of your question however sounds as if you do not pass in a node itself but rather a node name. Dynamic evaluation of a string with an XPath expression is not covered by the XSLT language, you would need to look into an extension function provided by the XSLT processor you use. Whether you really need that I am not sure, if you only have a single node name and not a path with several steps then doing something like xsl:when test="local-name() = $node-name" might suffice.

arunprasadlv · July 22nd, 2009, 08:48 AM

Iam trying to write a generic template which will copy all the elements from the source tree except the node i want to exclude which will be passed as an argument to this generic template.

Yes you are correct . Iam passing a node name to a named template.
if i try to execute a xpath node functions like count or any xpath expression ,iam getting the below error -

"value is not a node set" .

This error is because the node name is treated as string ,not a node set.

I read that exst:node-set() returns a node set for the argument passed.Can this function help me with this issue .

Any suggestions ....

Thanks,
Arun

mhkay · July 22nd, 2009, 08:58 AM

Please start a new thread for a new question - the archives get quite impossible to follow otherwise.

If $name is an element name, you can select elements with this name using

Code:

*[name()=$name]

Martin Honnen · July 22nd, 2009, 09:01 AM

exsl:node-set takes a result tree fragment as its argument, not a string with an element name.
If you want dynamic XPath evaluation then you need to use an extension function like http://www.saxonica.com/documentatio.../evaluate.html.
Whether you need that I am not sure, why can't you check xsl:when test="local-name() = $node-name" where node-name is the name of the parameter.

arunprasadlv · July 22nd, 2009, 09:19 AM

Martin - I can match the context node using local-name() but iam not able to write an xpath expression when condition is met .

I will start a new thread with the sample xml.

Thank You.