Copying all the nodes except the specific node

arunprasadlv · July 17th, 2009, 04:22 AM

Hi ,

input xml :

<?xmlversion="1.0"encoding="UTF-8"?>
<departments>
<employee1>
<salary>
<amount>30</amount>
</salary>
</employee1>
<employee2>
<amount>
<amount>40</amount>
</amount>
</employee2>
</departments>

xsl :

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"></xsl:output>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"></xsl:copy-of>
<xsl:apply-templates></xsl:apply-templates>
</xsl:copy>
</xsl:template>
<xsl:template match="*[local-name()='amount']|">
<xsl:element name="{name()}">
<xsl:call-template name="AnotherTemplate">
<xsl:with-param name="inputData" select="."></xsl:with-param>
</xsl:call-template>
</xsl:element>
</xsl:template>

<xsl:template name="AnotherTemplate">
<xsl:param name="inputData"></xsl:param>


</xsl:stylesheet>

Problem : I have written a xsl which copies all the elements from the source tree. I dont want to copy node "amount" from the source tree. So i have defined another template which matches on the node amount.

Now the problem is my input xml has got amount as a list. so I want to write a template which matches on the node "amount whose child is not amount.

Any suggestions to write template match satisfying above condition.

Thanks,
Arun

mrame · July 17th, 2009, 04:58 AM

Try this:

Code:

<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="amount">
<amount>
<xsl:call-template name="AnotherTemplate">
<xsl:with-param name="inputData" select="."></xsl:with-param>
</xsl:call-template>
</amount>
</xsl:template>

<xsl:template name="AnotherTemplate">
<xsl:param name="inputData"></xsl:param>
<!-- do some processing-->
</xsl:template>

<xsl:template match="amount[child::amount]">
<!-- do some processing-->
</xsl:template>

arunprasadlv · July 17th, 2009, 06:22 AM

mrame -

I modified the xsl as u suggested and its working. Here's the modified xsl

<xsl:stylesheet version="1.0"xmlns:xsl="http://www.w3.org/1999/XSL/Transform"xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"></xsl:apply-templates>
</xsl:copy>
</xsl:template>
<xsl:template match="amount">
<amount>
<xsl:call-template name="AnotherTemplate">
<xsl:with-param name="inputData" select="."></xsl:with-param>
</xsl:call-template>
</amount>
</xsl:template>
<xsl:template name="AnotherTemplate">
<xsl:param name="inputData"></xsl:param>
<out>
<xsl:value-of select="$inputData"></xsl:value-of>
</out>
</xsl:template>
<xsl:template match="amount[child::amount]">
<xsl:copy>
<xsl:apply-templates select="@* | node()"></xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

I have got few questions -

- what is the difference between two xpath statement if used in template match
<xsl:template match="amount/child::amount"> and
<xsl:template match="amount[child::amount]">

Do we have performance impact if we use the above logic to parse huge payload ?

Thanks,
Arun

joefawcett · July 17th, 2009, 06:39 AM

Quote:

Originally Posted by arunprasadlv

mrame -

I have got few questions -

- what is the difference between two xpath statement if used in template match
<xsl:template match="amount/child::amount"> and
<xsl:template match="amount[child::amount]">

Thanks,
Arun

amount/child::amount = amount/amount which gives elements named 'amount' that have a parent also called 'amount.

amount[child::amount] = amount[amount] which gives elements named 'amount' that have a child element also named 'amount'.
So both paths deal with elements like this

Code:

<amount><amount /></amount>

but the former matches the inner element and the latter the outer one.

mhkay · July 17th, 2009, 01:32 PM

Joe has answered you first question. As for the second:

Do we have performance impact if we use the above logic to parse huge payload ?

it's not clear what you're comparing with. Performance depends on what XSLT processor you are using, and the only reliable way to compare whether one construct is faster than another is to measure it.

arunprasadlv · July 17th, 2009, 01:53 PM

Michael -

I have requirement where i have to perform a specific transformation on the amount nodes,which can occur at different position in the source xml.

Instead of mapping all the elements induvidually , i am trying to write a filtering logic to copy all the element , but exculde the amount .For this node , the matching template will call another template which will do the required transformation to the amount field.

I will see if i can measure the performance with both the approaches.

One more question ,

<xsl:template match="amount[child::amount]>

the amount element has got a namespace prefix in the incoming xml.
How to use the local-name fn with child axis ?

Thanks,
Arun

samjudson · July 17th, 2009, 02:00 PM

Your best bet is to simply define the namespace in your XSLT and the use it:

<xsl:stylesheet ... xmlns:my="http://whaterever..."

<xsl:template match="my:amount[my:amount]">
..

joefawcett · July 17th, 2009, 02:00 PM

Quote:

Originally Posted by arunprasadlv

One more question ,

<xsl:template match="amount[child::amount]>

the amount element has got a namespace prefix in the incoming xml.
How to use the local-name fn with child axis ?
Thanks,
Arun

Why not just assign a nmamespace mapping?

Martin Honnen · July 17th, 2009, 02:01 PM

What is a local-name fn?
If you have elements in a namespace then have your XSLT stylesheet define a prefix (e.g. 'pf') for that namespace and do

Code:

<xsl:template match="pf:amount[child::pf:amount]">

arunprasadlv · July 22nd, 2009, 06:30 AM

Martin -

I want to make this template generic and call this template from my xsl , by passing the node (which i dont want to copy) as an argument to the generic template

So my generic template should check if the context node is the node which is passed as an argument, if not copy execute identity template else call another template.

- Is it possible to send the node as an argument ? Is there any way to convert the string into nodeset ?

Thanks
Arun